If the line L passing through point a (4,0) and the square of the curve (X-2) + the square of y = 1, what is the range of the slope of the line l If the line L passing through point a (4,0) and the square of curve (X-2) + the square of y = 1, what is the range of the slope of line l

If the line L passing through point a (4,0) and the square of the curve (X-2) + the square of y = 1, what is the range of the slope of the line l If the line L passing through point a (4,0) and the square of curve (X-2) + the square of y = 1, what is the range of the slope of line l

Is there a common point? Y-0 = K (x-4) kx-y-4k = 0 if there is a common point, it will intersect or tangent, so the distance from the center of the circle to the straight line is less than or equal to the radius (2,0) radius r = 1, so | 2k-0-4k | / √ (K & sup2; + 1) ≤ 1 | 2K | ≤ √ (K & sup2; + 1) square 4K & sup2; ≤ K & sup2; + 1K & sup2; ≤ 1 / 3 - √ 3 / 3 ≤ K ≤ √ 3 / 3