It is known that M is a point of hyperbola x ^ 2 / 12-y ^ 2 / 4 = 1 in the first quadrant, and f1.f2 is the left and right focus respectively If the absolute value of MF1 is greater than that of MF2 = 3, then the coordinates of point m are

It is known that M is a point of hyperbola x ^ 2 / 12-y ^ 2 / 4 = 1 in the first quadrant, and f1.f2 is the left and right focus respectively If the absolute value of MF1 is greater than that of MF2 = 3, then the coordinates of point m are

Let the coordinates of point m be (x, y)
a=√12===>2a=4√3,c=√(12+4)=4
The results show that mf1-mf2 = 4 √ 3, MF1 / MF2 = 3, MF1 = 6 √ 3, MF2 = 2 √ 3
Y²=MF1²-(c+X)²,Y²=MF2²-(c-X)²
∴(6√3)²-(4+X)²=(2√3)²-(4-X)²====>108-8X=12+8X
The hyperbolic equation of x = 6 is Y & sup2; = 8 = = = > y = 2 √ 2
The coordinate of point m is (6,2 √ 2)