Given that PA is perpendicular to the plane of rectangle ABCD, and ab = a, ad = B, PA = 2c, find the distance from the midpoint Q of PA to the straight line BD

The distance AE from a to BD is [under AB / radical (a + b)]
The distance from Q to BD is under the root sign (c + AE)=
Under root sign [(Party A * Party B + Party A * Party C + Party B * Party C) / (Party A + Party B)]

RELATED INFORMATIONS

1. PA is perpendicular to the plane of rectangle ABCD, and ab = 3cm, ad = 4cm, PA = 6 / 5 root 21cm. Calculate the distance from point P to BC and BD respectively
2. Given that PA is perpendicular to the plane of rectangle ABCD, AB is equal to four, BC is equal to three, PA is equal to one, the distance from P to straight line BD is
3. How many planes are equal to the four vertices of the space quadrilateral ABCD?
4. Find a point O in the quadrilateral ABCD to minimize the sum of the distances between it and the four vertices of the quadrilateral, and please give your reasons It's best to draw a picture to illustrate!
5. In the cube abcd-a1b1c1d1 with edge length 1, (1) find the distance from point a to plane BD1; (2) find the distance from point A1 to plane ab1d1; (3) find the distance between plane ab1d1 and plane BC1D; (4) find the distance from line AB to cda1b1
6. The edge length of cube abcd-a'b'c'd 'is 1. Find the distance from point C to plane c'bd
7. The triangle ABCD is a square, PD ⊥ face ABCD, PD = PC, e is the midpoint of PC,
8. As shown in the figure, the quadrilateral ABCD is a square, PD ⊥ plane ABCD, EC ∥ PD, and PD = 2ec. (I) prove: plane PBE ⊥ plane PBD; (II) if the dihedral angle p-ab-d is 45 °, find the sine value of the angle between the straight line PA and the plane PBE
9. The diamond ABCD is on the plane a, PA is perpendicular to a, and PC is perpendicular to BD
10. In the pyramid p-abcd, the bottom surface ABCD is a distance shape, PA ⊥ ABCD, the point E is on PC, and the PC ⊥ surface BDE In the pyramid p-abcd, the bottom surface ABCD is a distance shape, PA ⊥ ABCD, the point E is on PC, and the PC ⊥ surface BDE is: ① prove: the BD ⊥ surface PAC; ② if PA = 1, ad = 2, find: the tangent value of the face angle b-pc-a
11. Given that ABCD is a rectangle, ab = a, ad = B, PA ⊥ plane ABC, PA = C, then the distance from P to BC is? And the distance from P to BD is?
12. Given that ABCD is a rectangle, ab = a, ad = B, PA ⊥ plane ABC, PA = C, then the distance from point P to BC and BD is How to find two distances?
13. Through the vertex a of square ABCD, do PA ⊥ plane ABCD, PA = AB = 1, find the dihedral angle formed by plane APB and plane cpd
14. If the vertex a of the square ABCD passes through the line AP ⊥ plane ABCD, and AP = AB, then the degree of the dihedral angle formed by the plane ABP and the plane CDP is If you do well, you can pay me a picture, because I don't know how to draw a plane CDP
15. If the vertex a of the square ABCD passes through the AP vertical plane ABCD and AP = AB, then the degree of the dihedral angle between the plane ABP and the plane DCP is Draw a picture
16. If the line AP is perpendicular to the plane ABCD through the vertex a of the square ABCD, and AP = AB, then what is the dihedral angle between the plane ABP and the plane CDP? (Figure)
17. Given that PA ⊥ square ABCD, if AB = PA, then the dihedral angle of plane PAB and plane PCD is
18. Through the vertex a of the square ABCD, make the line PA ⊥ plane ABC, and PA = Pb, then the degree of the sharp dihedral angle formed by plane ABC and plane PCD is? Sorry, wrong number. It's not pa = Pb, it's PA = ab
19. PA is perpendicular to the plane of the square ABCD with side length a, PA = a, then the size of the dihedral angle b-pc-d is It needs a rough process
20. If the bottom of p-abcd is a parallelogram, the bottom of PA ⊥ is ABCD, the point E is on the side edge PC, and PE = 13pc, then VP − bdevp − ABCD=______ ．