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There is a point P in the square ABCD with side length 2. Find the minimum value of PA + Pb + PC. please write the procedure. 7. Ab There is a point P in the square ABCD with side length 2. Find the minimum value of PA + Pb + PC. please write the procedure 7. AB and AC are the diameter chord of circle O respectively, D is the point on inferior arc AC, De is perpendicular to ab at point h, intersecting circle O at point E, intersecting circle AC at point F, P is a point on extended line of ED
There is a point P in the square ABCD with side length 2. Find the minimum value of PA + Pb + PC. please write the procedure
To solve the proposition is to find the Fermat point of the isosceles right triangle ABC. The proof process is not listed, only the conclusion and the minimum value are given
The intersection of CE, BD, BD and CE is p. point P is the point where PA + Pb + PC is the minimum value, and CE is the minimum value of PA + Pb + PC
In the triangle CBE, from the cosine theorem, we get that:
CE^2=BE^2+BC^2-2BE*BC*cos∠ CBE=4+4-8cos150°=8+4√3
So CE = √ 6 + √ 2
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