In rectangular ABCD, the angle DEA = 30 degrees, e is a point on CD, and AE = AB = 8cm, find (1) the degree of angle EBC; (2) the area of triangle ade

(1) ∫ CD ∥ ab ∥ EAB = ∠ DEA = 30 ° and AE = AB, that is ∫ AEB is isosceles triangle ∥ Abe = ∠ AEB = (180 ° - 30 °) △ 2 = 75 ∥ EBC = ∠ ABC - ∠ Abe = 90 ° - 75 ° = 15 ° (2) in RT △ ade, ∫ DEA = 30 °, AE = 8cm ∥ ad = 4cm

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