In the trapezoid ABCD, AB is parallel to BC, the diagonal AC is perpendicular to BD, and AC is equal to 8 cm, BD is equal to 6 cm. What is the height of this trapezoid?

If B is taken as be / / AC, and the extension line of DC is crossed with E, ABEC is parallel to the edge of the car. So be is perpendicular to BD, be = AC = 8, CE = ab. according to Pythagorean theorem, de ^ 2 = DB ^ 2 + be ^ 2 = 36 + 64 = 100, de = 10, that is, CD + AB = CD + CE = de = 10, and because the area of trapezoid = the area of triangle DBE, (AB + CD) * height / 2 = 1 /

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