In the trapezoidal ABCD, if ad ‖ BC, diagonal AC ⊥ BD, and AC = 6cm, BD = 8cm, the length of the trapezoidal median line is equal to

The extension line of BC intersects with e because of AD / / BC, de / / AC so de = AC = 6cm, CE = ad because de / / AC, AC ⊥ BD so de ⊥ BD median line of trapezoid = 1 / 2 (AD + BC) = 1 / 2 (CE + BC) = 1 / 2 be because de ⊥ BD so be = BD square + de square so be = 10cm

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1. As shown in the figure, the four corners of rectangle ABCD are folded inward to form a seamless and overlapping quadrilateral efgh. If eh = 3cm and EF = 4cm, the length of side AB is () A. 4.6cmb. 4.8cmc. 5.0cmd
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