As shown in the figure, in the cuboid abcd-efgh, ab = BC = CD = Da = 4cm, FB = 3cm, if ant a walks 6cm per second, ant B walks 5cm per second (2) If ant a starts from point a, moves along the edge in the plane ABCD, and then goes back to point a (not in motion), ant B starts from point F, moves down along the edge FB, and then moves along the edge in the plane ABCD to point a (not in motion), and two ants start at the same time, then where do they meet? (except point a) (there are three answers)

As shown in the figure, in the cuboid abcd-efgh, ab = BC = CD = Da = 4cm, FB = 3cm, if ant a walks 6cm per second, ant B walks 5cm per second (2) If ant a starts from point a, moves along the edge in the plane ABCD, and then goes back to point a (not in motion), ant B starts from point F, moves down along the edge FB, and then moves along the edge in the plane ABCD to point a (not in motion), and two ants start at the same time, then where do they meet? (except point a) (there are three answers)

When B reaches point B, it takes 3 / 5 = 0.6 seconds
At this time, the distance of a is 6x0.6 = 3.6m
It's between AB and ab
The distance between B and a is 4-3.6 = 0.4m
Let's meet again after a second
6a=5a+0.4
A = 0.4 seconds
At this time, a walked 6x0.4 = 2.4m
So a total of 3.6 + 2.4 = 7 meters
That is, they meet at a distance of 1 meter between AB and C
There's only one