As shown in the figure, in the cuboid abcd-efgh, ab = BC = CD = Da = 4cm, FB = 3cm, if ant a walks 6cm per second, ant B walks 5cm per second (2) If ant a starts from point a, moves along the edge in the plane ABCD, and then goes back to point a (not in motion), ant B starts from point F, moves down along the edge FB, and then moves along the edge in the plane ABCD to point a (not in motion), and two ants start at the same time, then where do they meet? (except point a) (there are three answers)
When B reaches point B, it takes 3 / 5 = 0.6 seconds
At this time, the distance of a is 6x0.6 = 3.6m
It's between AB and ab
The distance between B and a is 4-3.6 = 0.4m
Let's meet again after a second
6a=5a+0.4
A = 0.4 seconds
At this time, a walked 6x0.4 = 2.4m
So a total of 3.6 + 2.4 = 7 meters
That is, they meet at a distance of 1 meter between AB and C
There's only one