26. Known: as shown in the figure, in square ABCD, e and F are the midpoint of AB and BC respectively, and CE and DF intersect at point G 26. Known: as shown in the figure, in square ABCD, e and F are the midpoint of AB and BC respectively, and CE and DF intersect at point G Verification: ad = AG

26. Known: as shown in the figure, in square ABCD, e and F are the midpoint of AB and BC respectively, and CE and DF intersect at point G 26. Known: as shown in the figure, in square ABCD, e and F are the midpoint of AB and BC respectively, and CE and DF intersect at point G Verification: ad = AG

Let the edge length of ABCD be a, then: DF = √ (a ^ 2 + (A / 2) ^ 2) = √ 5A / 2 as FH / / AB intersection CE is the median line of △ CBE at HFH, FH = be / 2 = AB / 4 = A / 4 △ FHG ~ △ dcgfg / Gd = FH / DC = 1 / 4fg / FD = FG / (FG + GD) = 1 / (1 + 4) = 1 / 5fg = FD / 5gd = fd-fg = 4fd / 5 = 2 √ 5A / 5 as AI ⊥ DG at I, because ∠ ADI = ∠ DFC