In the parallelogram ABCD, we know that E F is on the diagonal BD, e point is close to D f point is close to B, and AE / / CF indicates that ade congruent CBF

In the parallelogram ABCD, we know that E F is on the diagonal BD, e point is close to D f point is close to B, and AE / / CF indicates that ade congruent CBF

Proof: because ABCD is a parallelogram, so ad = CB, angle ace = angle CBF, and because AE / / CF, so angle AEB = angle CFD, so angle AED = angle CFB. In triangle ade and triangle CFB, angle AED = angle CFB, angle AC