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In the isosceles trapezoid ABCD, AD / / BC, ab = CD, e, N, F, m are the midpoint of edge AB, BC, CD, Da respectively, and EF ^ 2 + Mn ^ 2 = 8 Find the length of the diagonal of this isosceles trapezoid
Let's note that the intersection of EF and Mn is o ∵ e, N, F and m, which are the midpoint of edges AB, BC, CD and Da respectively ∵ en ∥ AC, MF ∥ AC ∥ en ∥ MF. Similarly, me ∥ NF ∥ menf is parallelogram ∵ en = 1 / 2Ac, me = 1 / 2bdac = BD ∥ me = en ∥ menf is diamond ⊥ Mn ⊥ EF, Mo = no, EO = fo ∥ EF ^ 2 + Mn ^ 2 = 4Eo # 178; + 4mo ∥
RELATED INFORMATIONS
- 1. It is known that, as shown in the figure, square ABCD, e, m, F and N are the points on ad, AB, BC and CD respectively. If EF ⊥ Mn, we prove that EF = Mn
- 2. As shown in the figure, in the trapezoidal ABCD, ad ‖ BC, ab = DC, m and N are the midpoint of AD and BC respectively, ad = 3, BC = 9, ∠ B = 45 °. Find the length of Mn
- 3. Known: as shown in the figure, in trapezoidal ABCD, ad ‖ BC, ∠ B = 60 °, C = 30 °, ad = 2, BC = 8 AB.CD It's a long story
- 4. As shown in the figure, in the ladder ABCD, AD / / BC,
- 5. As shown in the figure, in ladder ABCD, ad ‖ BC, ∠ B = 80 °, C = 50 °, ad = 2, BC = 5. Find the length of waist ab
- 6. As shown in the figure, in the trapezoidal ABCD, if ad ‖ BC, ∠ B = 72 °, C = 36 °, ad = 6cm, BC = 15cm, then CD=______ cm．
- 7. In trapezoidal ABCD, ad is parallel to BC, AB is equal to 13cm, BC is equal to 18cm, CD is equal to 15cm, ad is equal to 4cm, find the area of s trapezoidal ABCD
- 8. In the trapezoid ABCD. AD / / BC (AD is greater than BC). AB = CD, ∠ B = 60 °, ad = 15cm, BC = 49cm, then the waist length of the trapezoid is_____ cm.
- 9. As shown in the figure, in the square ABCD, e is the midpoint of AB side, G and F are the points on AD and BC side respectively. If Ag = 1, BF = 2, ∠ GEF = 90 °, then the length of GF is______ ．
- 10. In the quadrilateral ABCD, ab = DC, m and N are the midpoint of AD and BC, and GH is vertical to Mn, intersect AB and CD at point G respectively, and verify: ∠ AGH = ∠ DHG First, in the first row, are triangles similar?
- 11. In trapezoidal ABCD, AD / / BC, ∠ B = 40 ° and ∠ C = 50 °, e, m, F and N are the midpoint of AB, BC, CD and Da respectively, and EF = a, Mn = B 6. In trapezoidal ABCD, AD / / BC, ∠ B = 40 ° and ∠ C = 50 °, e, m, F and N are the midpoint of AB, BC, CD and ad respectively, and EF = a, Mn = B, then what is the length of BC? (expressed by the algebraic formula of a and b)! It's a process! hurry up!
- 12. As shown in the figure, in the trapezoidal ABCD, ad ∥ BC, ∠ B = 30 ° and ∠ C = 60 ° e, F, m and N are the midpoint of AB, CD, BC and Da respectively. Given BC = 7 and Mn = 3, then EF=______ ．
- 13. It is known that in the trapezoid ABCD. Ab | CD. E is the midpoint of BC. The angular extension line of the straight line AE intersecting DC is at point F D``C`````F `````````` `````E ```````` ````````` A````````B
- 14. In the parallelogram ABCD, we know that E F is on the diagonal BD, e point is close to D f point is close to B, and AE / / CF indicates that ade congruent CBF
- 15. As shown in the figure: in rectangular ABCD, ab = 2ad, e is a point on CD, and AE = AB, then ∠ CBE is equal to______ ．
- 16. As shown in the figure, in known rectangle ABCD, ab = 2ad, e is a point on CD and AE = AB, (1) calculate the degree of angle CBE, (2) if ad = 2cm, calculate the degree of angle CBE
- 17. E is a point on the edge CD of rectangle ABCD, and AE = AB, ab = 2BC, find the degree of ∠ EBC
- 18. Given AB = 2BC of rectangle ABCD, take point E on CD to make AE = EB, then the angle EBC is equal to A 60 B 45 C 30 D 15
- 19. Given AB = 2BC of rectangle ABCD, take point E on CD so that AE = EB, then what is the angle EBC equal to
- 20. As shown in the figure, in rectangular ABCD, e is a point on DC, AE = AB, ab = 2ad, then the degree of ∠ EBC is______ ．