Known: as shown in the figure, in trapezoidal ABCD, ad ‖ BC, ∠ B = 60 °, C = 30 °, ad = 2, BC = 8 AB.CD It's a long story
Set trapezoidal height H
8-2=6
h/tan30+h/tan60=6
The solution is h = 3 √ 3 / 2
So AB = h △ sin60 = 3 √ 3 / 2 × 2 / √ 3 = 3
CD=h÷sin30=3√3/2×2=3√3
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