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As shown in the figure, it is a square with side length of 6cm. E and F are the midpoint of CD and BC respectively
S Square = 6 × 6 = 36 (square centimeter), efbd = ofod = oeob = 0.5, s (OEF) s (ODE) = 0.5, because s (OEF) + s (ODE) = s (DEF) = 0.5s (CDF) = s (CEF) = 4.5 (square centimeter), s (EOF) = 13s (DEF) = 1.5 (square centimeter), s blank = s (DEF) + s (BCE) - S (EOF) - S (CEF) = 9 + 9-1.5-4.5 = 12 (square centimeter), s shadow = s (ABCD) - s blank = 36-12 = 24 (square centimeter) A: the area of the shadow is 24 square centimeters
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