Cut a 20 cm long wire into two sections, and make a square with the length of each section as the perimeter, then the minimum value of the sum of their areas is

Cut a 20 cm long wire into two sections, and make a square with the length of each section as the perimeter, then the minimum value of the sum of their areas is

Let the length of one segment be x and the length of the other segment be (20-x)
So the total area is s = (x / 4) · (x / 4) + (20-x) (20-x) / 16
When x = 10, there is a minimum area of 12.5 square centimeters