The figure on the right is a square with a side length of 6cm. E and F are the midpoint of CD and BC respectively. Find the area of the shadow in the figure

The area of the shadow part = the area of the triangle ABC + the area of the triangle BCG (G is the intersection of BF and CE). The area of the triangle ABC = 1 / 2, the area of the square ABCD = 12cm & # 178. In the triangle BCD, EF is the median line, so EF is parallel to BC, which proves that the triangle BCG is similar to the triangle EFG, EF = 1 / 2BC

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