The solution set of equation √ (sin2x) = √ (SiNx) is

The solution set of equation √ (sin2x) = √ (SiNx) is

√(sin2x)=√(sinx)
sin2x=sinx
2sinxcosx=sinx
(i) If SiNx = 0
Obviously
Then x = k π (K ∈ z)
(II) if SiNx ≠ 0
Then 2cosx = 1
That is, cosx = 1 / 2
So SiNx = √ (1 - (1 / 2) ^ 2) = √ 3 / 2
So x is in the first quadrant
Then x = 2K π + π / 3 (K ∈ z)
In conclusion, the solution set is {x | x = k π or 2K π + π / 3 (K ∈ z)}

Elden Ring Premiere

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