Given that 0 < x < 1, a > 0 and a ≠ 1, try to compare the size of | loga (1 + x) | and | loga (1-x) | and write the judgment process

Given that 0 < x < 1, a > 0 and a ≠ 1, try to compare the size of | loga (1 + x) | and | loga (1-x) | and write the judgment process

When a > 1, | loga (1-x) | - | loga (1 + x) | = - loga (1-x) - loga (1 + x) = - loga (1-x) = - loga (1-x2), ∵ 0 | 1-x | 1 + X, | 0 | 1-x2 | 1, | loga (1-x2) | 0, | loga (1-x) |