Solve the equation about X: loga (x2-x-2) = loga (X-2 / a) + 1 (a > 0 and a is not equal to 1)
loga(x^2-x-2)=loga[ax-2]
x^2-x-2=ax-2
x^2-(1+a)x=0
x=0,1+a
In order to make the equation meaningful, we also need to:
x^2-x-2>0 ==> x>2 or x0,==> x>2/a
So x = 0 is rounded off
When x = 1 + a > 2 / A, a ^ 2 + A-2 > 0, = = > a > 1 or A1, x = 1 + a
0
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