If the equation loga (x-3) - loga (x + 2) - loga (x-1) = 1 has real roots, where a > 0, the range of a is obtained
A is the bottom, a > 0, a ≠ 1
x>3
Loga (x-3) = 1 + loga (x + 2) + loga (x-1) is transformed into ax ^ 2 + (A-1) x + (3-2a) = 0
(a-1)^2 -4a(3-2a) ≥0
① - (A-1) / (2a) > 3 must have roots
②-(a-1)/(2a)
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