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a是底,a>0,a≠1 x>3 loga(x-3)=1+loga(x+2)+loga(x-1)化為ax^2 +(a-1)x+(3-2a)=0有根 (a-1)^2 -4a(3-2a)≥0 ①-(a-1)/(2a)>3必有根 ②-(a-1)/(2a)
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