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loga(x^2-x-2)=loga[ax-2] x^2-x-2=ax-2 x^2-(1+a)x=0 x=0,1+a 為使方程有意義,還需: x^2-x-2>0 ==> x>2 or x0,==> x>2/a 所以x=0舍去 x=1+a>2/a,得:a^2+a-2>0,==>a>1 or a1時,x=1+a 0
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