If y = log2 (x ^ 2 - ax + 1) has the minimum value, then the value range of a is 2 after log is the base | Math enthusiast | Mathematical art

If y = log2 (x ^ 2 - ax + 1) has the minimum value, then the value range of a is 2 after log is the base

Y = log2 (T) is an increasing function
It only needs x ^ 2-ax + 1 > 0, y = log2 [(x-a / 2) ^ 2 + 1-A ^ 2 / 4], that is, it only needs 1-A ^ 2 / 4 > 0
Get - 2

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