When the image of the first-order function y = k2x-k + 5 passes through the point (- 2,4), the inverse scale function y = K / X in the quadrant where the image is located, y increases with the increase of X

Passing through the point (- 2,4), substituting into 4 = - 2K ^ 2-k + 5, we get 2K ^ 2 + k-1 = 0, that is, (2k-1) (K + 1) = 0, we get k = 1 / 2, - 1
If y = K / x increases with the increase of X, then K

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