The Quasilinear equation of parabola y ^ 2 = 4x is x =? most urgent X=?
The parabolic standard equation is Y & sup2; = 2px (P > 0)
In this problem, P = 2, the Quasilinear equation is x = - P / 2 = - 1
Equation: x = - 1
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- 1. Given that the parabola y squared = - 8x, then the Quasilinear equation of the parabola is?
- 2. If the vertex of the parabola y = - x square - 2x + P is on the straight line y = x / 2-1, find the value of P, and then rewrite the expression of the parabola into the form of y = a (x + m) square + K
- 3. If there is only one common point between a straight line with a slope of 1 and a parabola y squared equal to 4x, then the equation of the straight line is In fact, I have done it, but to be sure, I still want to see the difference between other people's and mine~
- 4. The linear equation which passes through the fixed point P (0,1) and has only one common point with the parabola y2 = 2x is______ .
- 5. The Quasilinear equation of parabola y = 2x2 is______ .
- 6. If the line y = x + 3 and the parabola y = - x + 2x + 3 intersect at two points a and B, the area of the triangle with a, B and origin 0 as the vertex is obtained No picture, step, high score
- 7. An equilateral triangle with three vertices on the parabola y ^ 2 = 4x and a fixed point as the origin of the coordinate is used to calculate the area of the triangle
- 8. It is proved that at least one of the three parabola y = CX ^ 2 + 2aX + B, y = ax ^ 2 + 2bx + C, y = BX ^ 2 + 2cx + A. (a, B, C are non-zero real numbers) has intersection with X axis To the contrary, be more specific. Within an hour
- 9. Find the volume of the body of revolution formed by the ellipse x ^ 2 / 9 + y ^ 2 / 4 = 1 rotating around the X axis Need process! Urgent!
- 10. Find the volume of a rotating body (called a rotating ellipsoid) formed by the elliptic equation rotating around the x-axis Find the volume of the revolving body (called revolving ellipsoid) formed by the ellipse X & # 178 / / A & # 178; + Y & # 178 / / B & # 178; = 1 rotating around the X axis
- 11. The Quasilinear equation of parabola y2 = 4x is () A. x=1B. y=1C. x=-1D. y=-1
- 12. The equation of a circle with F as the center and ab as the diameter is______ .
- 13. It is known that the square of the line passing through the parabola y is equal to the focus F of 4x, and intersects with the parabola at two points a and B The first question is to find the area of the triangle ABO when the oblique line is 1. The second question is to find the trajectory equation of the midpoint m of the focus chord ab
- 14. What is the distance between the focus of the parabola y = - 12x and the directrix?
- 15. The distance from the focus of the parabola y2 = 10x to the collimator is () A. 52B. 5C. 152D. 10
- 16. Let the parabolic equation be x = 2Y ^ 2, and the distance from the focus to the collimator is equal to?
- 17. First, determine the opening direction, symmetry axis and vertex coordinates of the parabola y equal to the square of 1 / 2 x plus x minus 4, and draw the drawing at the tracing point
- 18. If the distance from point a to the focus on the parabola y ^ 2 = 2px is 3 and the abscissa of the point is 2, what is p equal to
- 19. If the square of the parabola y equals 2px (P > 0), the distance from a point m to the focus is a (a > P / 2), then the abscissa of point m is? I'd like to know why the coordinates of point m are half a,
- 20. If the square of the parabola y is equal to 2px (P is greater than 0), the distance between the big focus of the point with abscissa 2 is 3, then the value of P is 0