An equilateral triangle with three vertices on the parabola y ^ 2 = 4x and a fixed point as the origin of the coordinate is used to calculate the area of the triangle
Tilt angle π / 6
k=√3/3
So y = √ 3 / 3 * x
Substituting
x^2/3=4x
x=0,x=12
y=√3/3*x=4√3
So two vertices (12,4 √ 3), (0,0)
The side length is a
Then a ^ 2 = 192
S=√3/4*a^2=48√3
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