The Quasilinear equation of parabola y = 2x2 is______ ．

The equation of parabola can be changed to x2 = 12Y, so p = 14. The Quasilinear equation is y = - 18, so the answer is y = - 18

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15. The Quasilinear equation of parabola y ^ 2 = 4x is x =? most urgent X=?
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19. What is the distance between the focus of the parabola y = - 12x and the directrix?
20. The distance from the focus of the parabola y2 = 10x to the collimator is () A. 52B. 5C. 152D. 10