When a changes, the two tangent points are on the tangent line () respectively A:y=1/2 x²,y=3/2 x² B:y=3/2 x²,y=5/2 x² C:y=x²,y=3x² D:y=3x²,y=5x²

When a changes, the two tangent points are on the tangent line () respectively A:y=1/2 x²,y=3/2 x² B:y=3/2 x²,y=5/2 x² C:y=x²,y=3x² D:y=3x²,y=5x²

Y '= 2x + A, let the tangent point (x0, Y0), then the tangent is y-y0 = (2x0 + a) (x-x0) and the tangent passes through the origin, so Y0 = (2x0 + a) x0, the solution is a = Y0 / x0 - 2x0, substituting a and point (x0, Y0) into y = x & # 178; + ax + 4A & # 178;, Y0 = x0 & # 178; + y0-2x0 & # 178; + 4 (Y0 / x0 - 2x0) &# 178;, that is, 4 (Y0 / x0 - 2x0) &# 178