The tangent equation of parabola y ^ 2 = x with slope 2 is
A:
Parabola y ^ 2 = x
Derivation: 2yy '= 1
The slope k = y '= 2 is substituted into the above formula to get 2Y * 2 = 1
y=1/4
So: x = y ^ 2 = 1 / 16
So: the tangent point is (1 / 16,1 / 4)
The tangent equation is Y-1 / 4 = 2 (x-1 / 16) = 2x-1 / 8
So: the tangent is y = 2x + 1 / 8
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