The distance from the point P on the hyperbola x ^ 2 / 16-y ^ 2 / 9 = 1 to the right collimator is 12.5, and the distance from P to the right focus is calculated

RELATED INFORMATIONS

• 1. If the distance from a point P to one focus on the hyperbola X225 − Y29 = 1 is 12, then the distance from it to the other focus is 12______ ．
• 2. The distance between the intersection point of the vertical line and the hyperbola and the two focal points can be obtained by making the x-axis vertical line between the hyperbola (xsquare) / 144 - (ysquare) / 25 = 1 and the focal point Through a focus of hyperbola (xsquare) / 144 - (ysquare) / 25 = 1, make a vertical line of X axis, and find the distance from the intersection of the vertical line and hyperbola to the two focuses A = 2x root 5, through the point a (- 5,2), the focus is on the X axis, find the standard equation of hyperbola
• 3. Make a vertical line of X axis through a focus of hyperbola x square / 144-y square / 25 = 1, and calculate the distance from the intersection of the vertical line and hyperbola to the two focuses
• 4. If point P is on hyperbola & nbsp; x216 & nbsp; − y212 & nbsp; = 1 and its abscissa is the same as that of the right focus of hyperbola, then the distance between point P and the left focus of hyperbola is______ ．
• 5. The distance from a point P on the right branch of hyperbola x ^ 2 / 16-y ^ 2 / 9 = 1 to the left quasilinear is 18, then the distance from the point to the right focus is 18
• 6. The distance from a point on the left support of hyperbola x square / 9-y square / 16 = 1 to the left focus is 7, then the distance from this point to the right focus of hyperbola is 7
• 7. If the distance from the point P on the hyperbola x ^ 2 / 64-y ^ 2 / 36 = 1 to the right focus of the hyperbola is 8, then the distance from P to the right collimator is 8___ , P to the left collimator If the distance from the point P on the hyperbola x ^ 2 / 64-y ^ 2 / 36 = 1 to the right focus of the hyperbola is 8, then the distance from P to the right collimator is 8___ What is the distance from P to the left collimator___ .
• 8. If the distance from a point P on the hyperbola x264 − y236 = 1 to its right focus is 8, then the distance from point P to its right collimator is () A. 10B. 3277C. 27D. 325
• 9. The distance between a point P on hyperbola X & sup2 / 64-y & sup2 / 64 = 1 and its right focus is 8, then the distance between point P and its left quasilinear () A.10 B.32√7/7 C.12√2 D.32/5 From the known a & sup2; = B & sup2; = 64, we get e = √ 2, a & sup2 / / C = 4 √ 2. So the distance from point P to the right focus is 8 / E = 4 √ 2. And because a & sup2 / / C = 4 √ 2, so 2A & sup2 / / C = 8 √ 2. So the distance from P to the left quasilinear is 4 √ 2 + 8 √ 2 = 12 √ 2 Choose C
• 10. If the distance from a point P on hyperbola x2-y23 = 1 to the left focus is 4, then the distance from point P to the right collimator is () A. 1b. 2C. 3D. 1 or 3
• 11. On hyperbola x ^ 2 / 16-y ^ 2 / 9 = 1, if the distance from a point P to a focus is 12, then the distance from point P to another focus is?
• 12. Let p be a point on the hyperbola (x ^ 2 of 16) - (y ^ 2 of 9) = 1, and the distance from P to one focus of the hyperbola is 10, then what is the distance from P to another focus
• 13. Hyperbola 25 / x square - 9 / y square = 1 any point P is closer to this hyperbola, the distance from one focus is 2, find the distance from point P to another focus
• 14. Let f be the focus of the parabola y2 = 4x, and a, B, C be the three points on the parabola. If the center of gravity of the points a (1,2), △ ABC coincides with the focus F of the parabola, Then the equation of the line where the BC edge is located is
• 15. Let ABC be three different points on the parabola y2 = 4x, if the focus F of the parabola is exactly the center of gravity It is known that ABC is three different points on the parabola y ^ 2 = 4x. If the focus F of the parabola is exactly the center of gravity of the triangle ABC, then the value of AF + BF + CF is equal to?
• 16. What is the distance from point (3, - 6) to the focus of the parabola y square = 12x
• 17. If the abscissa of a point m on the parabola y2 = 16x is 6, then the distance from m to the focus f is 0______ ．
• 18. The square of parabola y = 2px (P > 0), the distance from a point m to the focus is a (a > P / 2), then what is the distance from point m to the collimator? The abscissa of point m is If the distance between a point m and the focus on the parabola y = 2px (P > 0) is a (a > P / 2), what is the distance between the point m and the collimator? What is the abscissa of the point m?
• 19. If the distance from a point m on the parabola y = 4x2 to the focus is 1, then the ordinate of point m is () A. 1716B. 1516C. 78D. 0
• 20. If the distance from a point m on the parabola y = 4x2 to the focus is 1, then the ordinate of point m is () A. 1716B. 1516C. 78D. 0