The distance between a point P on hyperbola X & sup2 / 64-y & sup2 / 64 = 1 and its right focus is 8, then the distance between point P and its left quasilinear () A.10 B.32√7/7 C.12√2 D.32/5 From the known a & sup2; = B & sup2; = 64, we get e = √ 2, a & sup2 / / C = 4 √ 2. So the distance from point P to the right focus is 8 / E = 4 √ 2. And because a & sup2 / / C = 4 √ 2, so 2A & sup2 / / C = 8 √ 2. So the distance from P to the left quasilinear is 4 √ 2 + 8 √ 2 = 12 √ 2 Choose C

From the known a & sup2; = B & sup2; = 64, we get e = √ 2, a & sup2 / / C = 4 √ 2. So the distance from point P to the right focus is 8 / E = 4 √ 2. And because a & sup2 / / C = 4 √ 2, so 2A & sup2 / / C = 8 √ 2. So the distance from P to the left quasilinear is 4 √ 2 + 8 √ 2 = 12 √ 2
Choose C

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