The projection of the intersection line of x ^ 2 + y ^ 2 under the equation z = x ^ 2 + y ^ 2 and z = 2-radical on xoy plane,

Equation z = x ^ 2 + y ^ 2
Equation z = 2 - √ (x ^ 2 + y ^ 2)
The projection on the xoy plane,
Then z = x ^ 2 + y ^ 2 = 2 - √ (x ^ 2 + y ^ 2)
That is (√ (x ^ 2 + y ^ 2)) ^ 2 + √ (x ^ 2 + y ^ 2) - 2 = 0
√(x^2+y^2)=1
That is Z = x ^ 2 + y ^ 2 = 1

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