Contact us
Choose a category below so we can get back to you as quickly as possible.
方程z=x^2+y^2 方程z=2-√(x^2+y^2) 在xoy面上的投影, 那麼z=x^2+y^2 =2-√(x^2+y^2) 即(√(x^2+y^2))^2+√(x^2+y^2)-2=0 √(x^2+y^2)=1 即z=x^2+y^2=1
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.