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設方程y²;=4px,則焦點(p,0),A在抛物線上,AF=5,則4pm=9,(m-p)²;+9=25,則 (m+p)²;=(m-p)²;+4pm=25,得|m+p|=5,|m-p|=4,因為焦點F在x軸的正半軸,可知m>0,p>0, 所以m與p分別是9/2與1/2,標準方程y²;=2x或y²;=18x
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