A quadratic equation How to calculate (3x-2] ^ 2 = 4 (x-3) ^ 2?
(3x-2〕^2=4(x-3)^2
(3x-2)(3x-2)=4(x-3)(x-3)
9x^2+4-12x=4(x^2+9-6x)
9x^2-4x^2-12x+24x=36-4
5x^2+12x-32=0
(5x-8)(x+4)=0
So X1 = 8 / 5, X2 = - 4
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