If we know that one focus of the ellipse is (√ 2,0), and the chord length of the tangent line x = √ 2 is (4 / 3) √ 6, then the elliptic equation is?
Let the elliptic equation be x ^ 2 / A ^ 2 + y ^ 2 / b ^ = 1
c=√2
a^2-b^2=c^2=2
The two focuses of string and equation are (√ 2, B ^ 2 / a) and (√ 2, - B ^ 2 / a)
∴2b^2/a=4√6/3
The solution is a ^ 2 = 6, B ^ 2 = 4 or a ^ 2 = 2 / 3, B = - 4 / 3 (rounding off)
The elliptic equation is x ^ 2 / 6 + y ^ 2 / 4 = 1
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