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The shortest chord length of the focus f (C, 0) passing through the ellipse x2a2 + y2b2 = 1 (a > b > 0) is () A. 2b2aB. 2a2bC. 2c2aD. 2c2b
According to the meaning of the title, the shortest chord of the chord passing through the focus f (C, 0) of the ellipse x2a2 + y2b2 = 1 (a > b > 0) is the chord passing through the focus perpendicular to the X axis. When x = C, y = ± B2A, the shortest chord length is 2b2a, so a
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