If we know that the two tangents of parabola C1: y2 = x + 1 and parabola C2: y2 = - x-a are perpendicular at the intersection, we can find a

If we know that the two tangents of parabola C1: y2 = x + 1 and parabola C2: y2 = - x-a are perpendicular at the intersection, we can find a

Y ^ 2 = x + 1, the derivative is 2Y * y '= 1, y' = 1 / 2yy ^ 2 = - x-a, the derivative is 2Y * y '= - 1, y' = - 1 / 2Y, let the intersection coordinate be (m, n), then K1 = y'1 = 1 / 2n, K2 = - 1 / 2n and k1k2 = - 1, so - 1 / (2n) ^ 2 = - 1, 4N ^ 2 = 1, n = soil 1 / 2, so 1 / 4 = m + 1, 1 / 4 = - M-A, the solution is 1 / 4 + 1 / 4 = 1-aa = 1 / 2