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dy/dx=(x+y^3)/xy^2
∵ dy / DX = (x + y ^ 3) / (XY ^ 2) = = > XY ^ 2dy = (x + y ^ 3) DX = = > y ^ 2dy / x ^ 3 = DX / x ^ 3 + y ^ 3DX / x ^ 4 (divide both ends of the equation x ^ 4) = = > d (y ^ 3) / (3x ^ 3) + y ^ 3D (1 / (3x ^ 3)) + D (1 / (2x ^ 2)) = 0 = = = > d (y ^ 3 / (3x ^ 3)) + D (1 / (2x ^ 2)) = 0 = = > y ^ 3 / (3x ^ 3) + 1 / (2x ^ 2) = C / 6 (C is a constant) =
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