General solution of (1 + y) DX - (1-x) dy = 0 | Math enthusiast | Mathematical art

General solution of (1 + y) DX - (1-x) dy = 0

(1 + y) DX - (1 - x) dy = 0 (1 + y) DX = (1 - x) dy [1 / (1 - x)] DX = [1 / (1 + y)] dyd (LN (1 - x)) = D (LN (1 + y)) ln (1 - x) + C1 = ln (1 + y) (C1 is any real number) 1 + y = e ^ [ln (1 - x) + C1] y = C * (1 - x) - 1 (C is any

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