It is known that 4x-3y-3z = x-3y + Z = 0 (x, y, Z are not equal to 0) (1) Find X: Y: Z (2) find the value of 2x + 3y-4z / Z

4x-3y-3z=x-3y+z=0
4x/z-3y/z-3=0.①
x/z-3y/z+1=0.②
① - 2: 3x / Z-4 = 0
Substituting X / z = 4 / 3 into 2, we get 4 / 3 + 1-3y / z = 0
y/z=7/9
x:y=(4/3)/(7/9)=4:(7/3)=12:7
x:z=12:9
x:y:z=12:9:7
2)
(2x+3y-4z)/z=2x/z+3y/z-4
=8/3+7/3-4
=5-4
=1

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