Tangent plane equation with curve z = x ^ 2 + y ^ 2 parallel to plane 2x + 4y-z = 0

If the normal vector of the curve is (2x, 2Y, - 1) = a (2,4, - 1), then x = 1, y = 2, then z = 5. Therefore, the tangent plane at point (1,2,5) is 2 (x-1) + 4 (Y-2) - (Z-5) = 0, that is, the
The tangent plane equation of curve z = x ^ 2 + y ^ 2 and plane 2x + 4y-z = 0 is 2x + 4y-z-5 = 0

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