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Find the linear equation (space line and equation) passing through point (0,2,4) and parallel to two planes x + 2Z = 1 and y-3z = 2
Plane x + 2Z = 1 normal vector: N1 = (1, 0, 2)
Plane y-3z = 2 normal vector: N2 = (0, 1, - 3)
And the direction vector s of the line L is perpendicular to N1 and N2
s = n1×n2 = ( -2, 3, 1 )
The point method equation of L is as follows
(x-0)/(-2) = (y-2)/3 = (z-4)/1
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