High number: solve the plane equation which passes through points a (1,2,0), B (2,3,2) and is perpendicular to the plane x-2y + Z = 0
Let ax + by + CZ + D = 0, AB line is on the plane, and the normal of x-2y + Z passing through point a is also on the plane. The cross product of these two line vectors is the normal vector of the plane, and then the equation can be solved by substituting AB point