The plane equation of the line x + y + Z-1 = 0,2x-y + 3Z = 0 and parallel to the line x = 2Y = 3Z is solved

The plane equation of the line x + y + Z-1 = 0,2x-y + 3Z = 0 and parallel to the line x = 2Y = 3Z is solved

First, find the standard form of the line. The tangent direction of the line passing through the point (0,3 / 4,1 / 4) is (1,1,1) × (2, - 1,3) = (4, - 1, - 3). The line can be written as the normal vector of X / 4 = (Y-3 / 4) / (- 1) = (Z-1 / 4) / (- 3) plane = (4, - 1, - 3) × (6,3,2) = (7, - 26,18). Let the plane square be 7x-26y + 18z + D = 0, and the plane pass through (0,3 / 4,1 / 4)