If the eccentricity of hyperbola x2 / m-y2 / N = 1 is 2 and there is a focal point coincident with that of parabola y2 = 4x, then the value of Mn is?

y²=2px=4x
So p / 2 = 1
Focus (1,0)
Divide by hyperbola C = 1
a=c/e=1/2
That is m = A & sup2; = 1 / 4
n=b²=c²-a²=3/4
mn=3/16

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