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If the left and right focuses of the ellipse x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1 are F1 and F2, and the segments F1 and F2 are divided into 5:3 segments by the focus of the parabola y2 = 2bx, then the eccentricity of the ellipse is
The focus of y2 = 2bx is (B / 2,0), (c + B / 2): (C-B / 2) = 5:3, C / 2 = B;
x^2/a^2+y^2/b^2=1,c^2=a^2-b^2;a^2=（c/2）^2+c^2=5c^2/4；
c/a=2√5/5
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