It is known that the eccentricity of ellipse C: x2 / A2 + Y2 / B2 = 1 (a > b > 0) is 2 / 3, passing through focus f (C, 0) and point B (0, 0), Urgent, final exam

It is known that the eccentricity of ellipse C: x2 / A2 + Y2 / B2 = 1 (a > b > 0) is 2 / 3, and the distance from the line passing through focus f (C, 0) and point B (0, - b) to the origin is 2 / 3?
In the right triangle oBf, BF = C, OB = B, so BF = B + C = a, where BF = a, so 2 / 2 root 3 = (BC) / A, so 3A = 4B (a-b), and E = 2 / 2 root 3, so 3A = 4 (a-b), the two equations are solved to a = 4, B = 1, and the elliptic equation is obtained
x2/4+y2=1

RELATED INFORMATIONS

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