Find the focus and focal length of ellipse: 2x ^ 2 + y ^ 2 = 8; 3x ^ 2 + 4Y ^ 2 = 12

First, the standard x ^ 2 / 4 + y ^ 2 / 8 = 1, we can see that the focus is on the Y axis, a ^ 2 = 8, B ^ 2 = 4, C ^ 2 = 4, C = 2, so the focal length is 2C = 4, and the focal coordinate is (0,2) (0, - 2)
Another method is the same, the focus is on the X axis, a ^ 2 = 4, B ^ 2 = 3, so C ^ 2 = 1, C = 1, the focal length is 2C = 2, the focus is (1,0) (- 1,0)

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