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It is known that the eccentricity of the ellipse e is e, the two focal points are F1 and F2, the parabola C takes F1 as the vertex, F2 as the focal point, and P is a common point of the two curves. If | Pf1 | PF2 | = e, then the value of E is () A. 33B. 32C. 22D. 63
Let's note that the x-axis of the collimator l of the parabola intersects with m, and the projection of P on L is Q, then | f1m | = | F1F2 | = 2c, that is, the equation of L is x = - 3C, | PF2 | = | PQ |, and | Pf1 | PF2 | = e, that is, | Pf1 | | PQ | = e, ∵ F1 is the left focus of the ellipse, | | PQ | is the distance from P to the left collimator of the ellipse, that is, l is the left collimator of the ellipse, so we choose a as follows: - 3C = - A2C {e = 33
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