If the vertex B of the square oabc and the vertex e of the square ADEF are both on the image of the function y = 1 / X (x > 0), what are the coordinates of the point e

If the vertex B of the square oabc and the vertex e of the square ADEF are both on the image of the function y = 1 / X (x > 0), what are the coordinates of the point e

B（1,1）
Let the side length of square ADEF be n
Then E (1 + N, n) is on y = 1 / X
That is, (1 + n) n = 1
n^2+n-1=0
Using the formula of root
A = (- 1 ＋ 5) / 2 (because a > 0)
The coordinates of E are ((1 ＋ 5) / 2, (- 1 ＋ 5) / 2)

Elden Ring Premiere

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